Q. Molar conductance of electrolytic solution $\Lambda_{m}$ is
A) $\propto \ l$
B) $\propto \ (1/A)$
C) $\propto \ (1/C)$
D) $\propto \ (\sqrt{C})$
Explanation
(c)
Molar conductivity or molar conductance
$\left( \Lambda_{m} \right) = \ \kappa\ \times V$
$\Lambda_{m} = \kappa\ \times \ \frac{1000}{C_{m}}$
Where, $C_{m}$ is molar concentration $(mol\ L^{- 1})$
∴ Molar conductance $(\Lambda_{m})\ \propto \ (\frac{1}{C})$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.