Q. Two different electrolytic cells filled with molten $Cu({NO}_{3})_{2}$ and molten $Al({NO}_{3})_{3}$ respectively are connected in series. When electricity is passed 2.7 g Al is deposited on electrode. Calculate the weight of Cu deposited on cathode. $\lbrack Cu = 63.5;Al = 27.0\ g\ {mol}^{- 1}$ ]
A) 190.5 g
B) 9.525 g
C) 63.5 g
D) 31.75 g
Explanation
(b)
$\frac{wt.of\ Al\ deposited}{wt.of\ Cu\ deposited} = \frac{eq.wt.of\ Al}{eq.wt.of\ Cu}\$
$\frac{2.7}{wt.of\ Cu} = \frac{27/3}{63.5/2}$
wt. of Cu = 9.525 g
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.