The ionic conductance of ${Ba}^{2 +}\$ and ${Cl}^{-}$ are respectively 127 and 76 $\mathrm{\Omega}^{- 1}\ {cm}^{2}$ at infinite dilution. The equivalent conductance (in $\mathrm{\Omega}^{- 1}\ {cm}^{2}$) of ${BaCl}_{2}$ at infinite dilution will be

Question

Dr. Abubacker · Accepted Answer

(a)
$\Lambda_{m}^{\infty}\ for\ {BaCl}_{2} = \ \Lambda_{m}^{\infty}\ {Ba}^{2 +} + \ 2\Lambda_{m}^{\infty}\ \ {Cl}^{-}\ \$
∴ $\Lambda_{eq}^{\infty}\ for\ {BaCl}_{2} = 1/2\Lambda_{m}^{\infty}\ {Ba}^{2 +} + \ \Lambda_{m}^{\infty}\ {Cl}^{-}\ \$
$= 127\ /\ 2\  + \ 76\$
$= 139.5\ \mathrm{\Omega}^{- 1}\ {cm}^{2}$

Q. The ionic conductance of ${Ba}^{2 +}\$ and ${Cl}^{-}$ are respectively 127 and 76 $\mathrm{\Omega}^{- 1}\ {cm}^{2}$ at infinite dilution. The equivalent conductance (in $\mathrm{\Omega}^{- 1}\ {cm}^{2}$) of ${BaCl}_{2}$ at infinite dilution will be

Explanation

Reviewed by Dr. Abubacker

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