Q. The desired amount of charge for obtaining one mole of Al from ${Al}^{3 +}$ is
A) 96500 C
B) $2 \times 96500\ C$
C) $3 \times 96500\ C$
D) $\frac{96500}{2}\ C$
Explanation
(c)
$Al\ \rightarrow {Al}^{3 +} + 3e^{-}$
The charge required $= 3 \times 96500\ C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.