(d)
The cell reaction is,
$\frac{1}{2}\ H_{2}(g)$ + AgCl(s)$\longrightarrow \ H^{+}(aq) + \ {Cl}^{-}(aq) + \ Ag\ (s)$
Obviously, here hydrogen is being oxidized and AgCl is getting reduced. Hence, the correct cell representation will be
Pt | $H_{2}(g)$ , HCl solution || AgCl(s) | $Ag$