Q. Ionic mobility of ${Ag}^{+}\$ is ( $\lambda_{\ Ag^{+}}\ = 5 \times 10^{- 1}\ \mathrm{\Omega}^{- 1}\ {cm}^{2}\ \ {equiv}^{- 1}\$)
A) $5.2 \times 10^{- 9}$
B) $2.4 \times 10^{- 9}$
C) $1.52 \times 10^{- 9}$
D) $8.25 \times 10^{- 9}$
Explanation
(a)
Ionic mobility
$µ_{{Ag}^{+}} = \frac{ionic\ conductance}{96500}$
${= \ \frac{5\ \times \ 10^{- 4}}{96500}
}{= \ 5.2 \times 10^{- 9}cm/s}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.