Q. The conductivity of a 0.01 N solution is found to be $0.005\ {ohm}^{- 1}\ {cm}^{- 1}.$ The equivalent conductivity of the solution will be
A) $5 \times 10^{- 2}\ {ohm}^{- 1}\ {cm}^{2}\ {equiv}^{- 1}$
B) $5.00 \times 10^{- 3}\ {ohm}^{- 1}\ {cm}^{2}$
C) $500\ {ohm}^{- 1}\ {cm}^{- 2}\ {equiv}^{- 1}$
D) $0.5\ {ohm}^{- 1}\ {cm}^{2}\ {equiv}^{- 1}$
Explanation
(c)
$\Lambda_{eq}^{{^\circ}} = \kappa \times \frac{1000}{normality}$
$= \frac{0.005\ \times 1000}{0.01} = 500\ {ohm}^{- 1}\ {cm}^{2}\ {equiv}^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.