Q. The product obtained at anode when 50% $H_{2}{SO}_{4}$ aqueous solution is electrolysed using platinum electrodes is
A) $H_{2}{SO}_{3}$
B) $H_{2}S_{2}O_{8}$
C) $O_{2}$
D) $H_{2}$
Explanation
(b)
50 % $H_{2}{SO}_{4}$aqueous solution can be electrolysed by using Pt electrodes as
${2H}_{2}\ {SO}_{4}\ \rightarrow \ 2HSO_{4}^{-}\ + \ {2H}^{+}$
$2HSO_{4}^{-}\ \rightarrow \ H_{2}S_{2}O_{8} + \ {2e}^{-}\ \ \ \ \$(at anode)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.