Q. The equivalent conductances of two strong electrolytes at infinite dilution in $H_{2}O$ (where ions move freely through a solution) at 25$℃$ are given below $\Lambda{^\circ}_{CH_{3}COONa} = 91.0\ S\ {cm}^{2}/equiv$ $\Lambda{^\circ}_{HCl} = 426.2\ S\ {cm}^{2}/equiv$ What additional information/quantity one needs to calculate $\Lambda{^\circ}$ of an aqueous solution of acetic acid?

A) $\Lambda{^\circ}\$of NaCl
B) $\Lambda{^\circ}$ of C$H_{3}$ COOK
C) The limiting equivalent conductance of $H^{+}({\lambda{^\circ}}_{H^{+}})$
D) $\Lambda{^\circ}$ of chloroacetic acid ($ClCH_{2}\ COOH$)
Explanation

(a)
We know from Kohlrausch’s law
$\bigwedge_{{CH}_{3}COOH}^{{^\circ}} = \ \bigwedge_{{CH}_{3}COONa}^{{^\circ}} + \ \bigwedge_{HCl}^{{^\circ}} - \ \bigwedge_{NaCl}^{{^\circ}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.