Q. The $E{^\circ}$ for half-cell ${Fe/Fe}^{2 +}\$and$\ {Cu/Cu}^{2 +}\$are$\ - 0.44\ V\$and$\ + 0.32\ V$ respectively, then

A) ${Cu}^{2 +}\ oxidises\ Fe$
B) $Cu\ oxidises\ {FeFe}^{2 +}$
C) $Cu\ reduces\ {Fe}^{2 +}$
D) ${Cu}^{2 +}\ oxidises\ {Fe}^{2 +}$
Explanation

(a)
Fe is more electropositive than copper
Hence, ${Cu}^{2 +}$ can oxidize Fe

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.