Q. Electrode potential of ${Zn}^{2 +}/Zn$ is – 0.76 V and that of $\ {Cu}^{2 +}/Cu$ is + 0.34 V. The emf of the cell constructed between these two electrodes is
A) 1.10 V
B) $- \ 1.10$ V
C) 2.20 V
D) $- \ 2.20$ V
Explanation
The correct answer is Option A: 1.10 V.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.