
(d)
As $AgnO_{3}$ is added to solution , KCl will be displaced according to following reaction $AgNO_{3}\ (aq) + \ KCl\ (aq) \longrightarrow AgCl_{(s)} + \ KNO_{3}\ (aq)$
For every mole of KCl displaced from solution, one mole of $KNO_{3}$ comes in solution resulting in almost constant conductivity. As the end point is reached, added $AgNO_{3}$ remain in solution increasing ionic concentration, hence conductivity increases.