Q. The relationship between Gibbs’ free energy change ($\Delta G$) and emf ($E$) of a reversible electrochemical cell is given by
A) $\Delta G = \ nFE$
B) $\Delta G\ = \ nF/E$
C) $\Delta G\ = - nFE$
D) $\Delta G = \ E/nF$
Explanation
(c)
The Gibb’s free energy change $\bigtriangleup G$ and emf ($E^{{^\circ}}$) of a reversible electrochemical cell are related by the following expression.
$\bigtriangleup G\ = \ - \ {nFE}_{cell}^{{^\circ}}$
or $= \ - \ nFE$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.