(c)
According to Faraday’s second law of electrolysis, we have
$\frac{w_{1}}{w_{2}} = \ \frac{E_{1}}{E_{2}}$
∴ $\frac{1.08}{x} = \ \frac{108}{1}\$
∴ Weight of hydrogen $(x)\ = \ 0.01\ g$
Hence, the volume of hydrogen at
$\ \ \ STP\ = \ \frac{22400\ \times 0.01}{2} = 112\ {cm}^{3}$