Q. A solution of sodium sulphate in water is electrolysed using inert electrodes. The products at the cathode and anode are respectively
A) $H_{2},\ O_{2}$
B) $O_{2},\ H_{2}$
C) $O_{2},\ Na$
D) $O_{2},\ {SO}_{2}$
Explanation
(a)
At cathode $2H^{+} + 2e^{-} \rightarrow H_{2}$
At anode $\ 2{OH}^{-} \rightarrow H_{2}O + \frac{1}{2}O_{2} + 2e^{-}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.