Q. 5 A is passed through a solution of zinc sulphate for 40 min. Find the amount of zinc deposited at the cathode
A) 4.065 g
B) 8.065 g
C) 16.065 g
D) 32.065 g
Explanation
(a)
$w = Zit$
$\therefore w = \frac{32.69 \times 5 \times 60 \times 40}{96500} = 4.065\ g$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.