In acidic medium $MnO_{4}^{-}$ is converted to ${Mn}^{2 +}$. The quantity of electricity in faraday required to reduce 0.5 mole of $MnO_{4}^{-}$ to ${Mn}^{2 +}$ would be

Question

Dr. Abubacker · Accepted Answer

(a)
In ${MnO}_{4}^{-}$ the oxidation number of Mn is + 7.
+7 +2
∴ $Mn\  + \ {5e}^{-} \longrightarrow \ Mn$
In the reaction, 5 electrons are involved hence 5 Faraday will be needed for the reduction of 1 mole of ${MnO}_{4}^{-}.$
Therefore, for 0.5 mole of ${MnO}_{4}^{-},$ number of Faradays required = 2.5 F

Q. In acidic medium $MnO_{4}^{-}$ is converted to ${Mn}^{2 +}$. The quantity of electricity in faraday required to reduce 0.5 mole of $MnO_{4}^{-}$ to ${Mn}^{2 +}$ would be

Explanation

Reviewed by Dr. Abubacker

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