Q. The standard emf of a cell involving one electron change is found to be 0.591 V and 25 ℃. The equilibrium constant of the reaction is ($F\ = \ 96500\ C\ {mol}^{- 1}$)
A) $1.0\ \times \ 10^{1}$
B) $1.0\ \times \ 10^{5}$
C) $1.0\ \times \ 10^{10}$
D) $1.0\ \times \ 10^{30}$
Explanation
(c)
$E_{cell}^{{^\circ}} = \ \frac{2.303RT}{nF}\log K_{eq}$
$E_{cell}^{{^\circ}} = \ \frac{0.0591}{n}\log K_{eq}$ [At 298 K]
$0.591\ = \ \frac{0.0591}{1}\log K_{eq}$
∴ $\log K_{eq}$ = 10
∴ $\ \ \ K_{eq}\ = \ 1\ \times \ 10^{10}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.