Q. The standard emf of a galvanic cell involving 2 moles of electrons in its redox reaction is 0.59 V. The equilibrium constant for the redox reaction of the cell is
A) $10^{20}$
B) $10^{5}$
C) 10
D) $10^{10}$
Explanation
(a)
$E_{cell}^{{^\circ}} = \ \frac{0.0591}{2}\log K_{c}$
$0.59\ = \ \frac{0.0591}{2}\log K_{c}$
$\frac{0.59 \times 2}{0.059} = \ \log K_{c}$
∴ $\log K_{c} =$20
$K_{c}$ = antilog 20 = $10^{20}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.