$E^{{^\circ}}$ $for\ {Fe}^{2 +}\ + \ {2e}^{-}\ \rightarrow \ Fe$ is -0.44 V and $E^{{^\circ}}$ for ${Zn}^{2 +}\ + \ {2e}^{-}\ \rightarrow \ Zn$ is -0.76 V thus

Question

Dr. Abubacker · Accepted Answer

(a)
High value for $E_{red}^{{^\circ}}$. Shows more electronegativity $i.e.,$ Zn is more electropositive than Fe. ($E_{{Zn}^{2 +}/Zn}^{{^\circ}} < \ E_{{Fe}^{2 +}\ /Fe}^{{^\circ}}$ )

Q. $E^{{^\circ}}$ $for\ {Fe}^{2 +}\ + \ {2e}^{-}\ \rightarrow \ Fe$ is -0.44 V and $E^{{^\circ}}$ for ${Zn}^{2 +}\ + \ {2e}^{-}\ \rightarrow \ Zn$ is -0.76 V thus

Explanation

Reviewed by Dr. Abubacker

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