(b)
The cathode and anode reactions respectively are
${Cu}^{2 +} + \ 2e^{-} \rightarrow Cu$
$2{Cl}^{-} \rightarrow {Cl}_{2} + 2e^{-}$
The two moles of electrons have been transferred from anode to cathode to produce Cu and$\ {Cl}_{2}$ in a mole ratio of 1:1. Thus, 2F electricity is required