If the standard electrode potential of ${Cu}^{2 +}$ / Cu electrode is 0.34 V, what is the electrode potential at 0.01 M concentration of ${Cu}^{2 +}$? ($T\ = \ 298\ K$)

Question

Dr. Abubacker · Accepted Answer

(b)
$E_{cell} = \ E_{cell}^{{^\circ}} + \ \frac{0.059}{n}\log{\lbrack M^{n +}brack}$
$E_{cell} = \ 0.34\  + \ \ \frac{0.059}{2}\log 10^{- 2}$
$= \ 0.34\  + \ \frac{0.059}{2}\  	imes \  - 2$
= + 0.281 V

Q. If the standard electrode potential of ${Cu}^{2 +}$ / Cu electrode is 0.34 V, what is the electrode potential at 0.01 M concentration of ${Cu}^{2 +}$? ($T\ = \ 298\ K$)

Explanation

Reviewed by Dr. Abubacker

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