Q. The number of coulombs required to reduce 12.3 g of nitrobenzene to aniline, is
A) 96500 C
B) 5790 C
C) 95700 C
D) 57900 C
Explanation
(d)
$C_{6}H_{5}{NO}_{2}\ + 6H^{+} + \ 6e^{-} \rightarrow C_{6}H_{5}{NH}_{2} + \ 2H_{2}O$
1 mol = 123 g nitrobenzene requires 6 mol electrons
$= 6 \times 96500\ C\ charge$
$\therefore$12.3 g nitrobenzene will require$\ = \frac{6 \times 96500 \times 12.3}{123}$
$= 6 \times 9650 = 57900\ C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.