(a) ${Ag}^{+} + e^{-} \rightarrow Ag,\ E_{Ag} = \frac{atomic\ mass}{1} = 108$ $Number\ of\ faraday = \frac{w_{Ag}}{E_{Ag}} = \frac{108}{108} = 1$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.