Q. Which substance is obtained in the solution on electrolysis of aqueous $Cu{SO}_{4}$ solution using graphite electrodes?
A) $H_{2}O$
B) $H_{2}{SO}_{4}$
C) ${Na}_{2}{SO}_{4}$
D) $Cu(OH)_{2}$
Explanation
(a)
At anode
${2H}_{2}O(l) \rightarrow O_{2}(g) + \ 4\ H^{+}(aq) + \ {4e}^{-}$
At cathode
${2Cu}^{2 +}(aq) + \ {4e}^{-}\ \rightarrow 2Cu(s)$
Net electrolysis reaction is
${2Cu}^{2 +}(aq) + \ {2H}_{2}O(l)\ \rightarrow 2Cu(s) + \ 4\ H^{+}(aq) + O_{2}(g)$
So, $\ H_{2}O$ is obtained.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.