(d) $E_{cell}^{{^\circ}}$= $\frac{2.303RT}{nF}\log K_{eq}$ 0.295 = $\frac{0.0591}{2}\log K_{eq}$ ∴ $\log K_{eq}$ = 10 ∴ $K_{eq} = 10^{10}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.