(b)
$NaCl\ + \ {KNO}_{3}\ \longrightarrow \ {NaNO}_{3} + \ KCl\$
$KCl\ –\ NaCl$
Molar conductivities 152 128
Difference $= \ 24\ S\ {cm}^{2}\ {mol}^{- 1}$
Molar conductivities of ${KNO}_{3}$ = 111
Molar conductivities of ${NaNO}_{3}$ = 111 – 24
$= \ 87\ S\ {cm}^{2}\ {mol}^{- 1}$