Q. [table] Electrolyte | KCl | $\mathbf{KN}\mathbf{O}_{\mathbf{3}}$ | HCl | NaOAc | NaCl ; $\mathbf{\Lambda}^{\mathbf{\infty}}\mathbf{(S\ }\mathbf{cm}^{\mathbf{2}}$ $\mathbf{mol}^{\mathbf{- 1}}\mathbf{)}$ | 149.9 | 145.0 | 426.2 | 91.0 | 126.5 [/table] Calculate $\Lambda_{HOAc}^{\infty}$ using appropriate molar conductances of the electrolytes listed above at infinite dilution in $H_{2}O$ at 25℃.
A) 217.5
B) 390.7
C) 552.7
D) 517.2
Explanation
(b)
$\Lambda_{AcOH}^{\infty} = \Lambda_{AcONa}^{\infty} + \ \Lambda_{HCl}^{\infty} - \ \Lambda_{NaCl}^{\infty}\$
= 91.0 + 426.2 – 126.5
= 390.7
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.