Q. On passing 3 A of electricity for 50 min, 1.8 g metal deposits. The equivalent mass of metal is
A) 9.3
B) 19.3
C) 38.3
D) 39.9
Explanation
(b)
$w_{metal} = \frac{E \times i \times t}{96500} = \frac{E \times 3 \times 50 \times 60}{96500}$
$\therefore E = \frac{96500 \times w}{3 \times 50 \times 60} = \frac{96500 \times 1.8}{3 \times 50 \times 60} = 19.3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.