Q. Standard electrode potential of cell $H_{2}\ |\ H^{+}\ ||{Ag}^{+}\ |\ Ag$ is
A) 0.8 V
B) -0.8 V
C) -1.2 V
D) 1.2 V
Explanation
(a)
$E_{cell}$ = $E_{C} - \ E_{A}$
Given, $E_{{Ag}^{+}\ /Ag}^{{^\circ}}$ = 0.80 V
$H_{2}$ | $H^{+}$ || ${Ag}^{+}$ | Ag
∴ Hydrogen is anode and silver is cathode.
$E_{cell}$ = $E_{C} - \ E_{A}$
= 0.80 – 0 (∵$E_{H^{+}/H}^{{^\circ}} = 0$)
= 0.80 V
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.