(b) $\frac{Weight\ of\ Cu}{Weight\ of\ H_{2}} = \frac{Eq.wt.of\ Cu}{Eq.wt.of\ H_{2}}$ $\frac{Weight\ of\ Cu}{0.504} = \frac{63.6/2}{1}$ $\therefore\$Weight of Cu$\ = 15.9\ g$
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