Q. For a first order reaction, $A \rightarrow$ products, the rate of reaction at $\lbrack A\rbrack = 0.2\ M$ is $1.0 \times 10^{- 2}\ mol\ L^{- 1}\min^{- 1}.$ The half-life period for the reaction is

A) 476 s
B) 496 s
C) 832 s
D) 242 s
Explanation

(c)
Rate $= k\lbrack A\rbrack$
$\therefore k = \frac{10^{- 2}}{0.2} = 5 \times 10^{- 2}$
Now, $t_{1/2} = \frac{0.693}{k} = \frac{0.693}{5\ \times \ 10^{- 2}} = 13.86\ \min$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.