(c) Rate $= k\lbrack A\rbrack$ $\therefore k = \frac{10^{- 2}}{0.2} = 5 \times 10^{- 2}$ Now, $t_{1/2} = \frac{0.693}{k} = \frac{0.693}{5\ \times \ 10^{- 2}} = 13.86\ \min$
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Ph.D. in Physics with 19+ years of teaching experience.