Q. A graph plotted between $\log k\ versus\ \frac{1}{T}$ for calculating activation energy is shown by
A) [image:4_image1.emf]
B) [image:4_image2.emf]
C) [image:4_image3.emf]
D) [image:4_image4.emf]
Explanation
(b)
A graph plotted between $\log k\ versus\ \frac{1}{T}$ for calculating activation energy is shown as:
[image:4_image20.emf]
From Arrhenius equation
$\log k = \log A - \frac{E_{a}}{2.303\ RT}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.