Q. For the reaction, $N_{2} + 3H_{2} \rightleftharpoons 2{NH}_{3}$ the rate of change of concentration for hydrogen is $- 0.3 \times 10^{- 4}\ {Ms}^{- 1}.$ The rate of change of concentration of ammonia is
A) $- 0.2 \times 10^{- 4}$
B) $0.2 \times 10^{- 4}$
C) $0.1 \times 10^{- 4}$
D) $0.3 \times 10^{- 4}$
Explanation
(b)
$N_{2} + 3H_{2} \rightleftharpoons 2{NH}_{3}$
$\frac{d\left\lbrack H_{2} \right\rbrack}{dt} = - 0.3 \times 10^{- 4}\ {Ms}^{- 1}$
$Rate = - \frac{1}{3}\frac{d\left\lbrack H_{2} \right\rbrack}{dt} = + \frac{1}{2}\frac{d\left\lbrack {NH}_{3} \right\rbrack}{dt}$
$= \frac{d\left\lbrack {NH}_{3} \right\rbrack}{dt} = - \frac{2}{3}\frac{d\left\lbrack H_{2} \right\rbrack}{dt}$
$= - \frac{2}{3} \times \left( - 0.3 \times 10^{- 4} \right)$
$= 0.2 \times 10^{- 4}\ {Ms}^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.