Q. For the reaction, $2N_{2}O_{5}(g) \rightarrow 4NO_{2}(g) + O_{2}(g)$ If the concentration of $NO_{2}$ increase by $5.2 \times 10^{- 3}M$ in 100 s then the rate of the reactions
A) $1.3 \times 10^{- 5}Ms^{- 1}$
B) $0.5 \times 10^{- 4}Ms^{- 1}$
C) $7.6 \times 10^{- 4}Ms^{- 1}$
D) $2 \times 10^{- 3}Ms^{- 1}$
Explanation
(a)
$Rate\ of\ reaction\ = \frac{1}{4}\frac{d\left( NO_{2} \right)}{dt} = \frac{5.2 \times 10^{- 3}}{4 \times 100}$
$= 1.3 \times 10^{- 5\ }Ms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.