Q. In the sequence of reaction, $A\overset{\ \ \ \ \ k_{1}\ \ \ \ \ }{\rightarrow}B\overset{\ \ \ \ \ k_{2}\ \ \ \ \ }{\rightarrow}C\overset{\ \ \ \ \ k_{3}\ \ \ \ \ }{\rightarrow}D\ k_{3} > k_{2} > k_{1}$ then the rate determining step of reaction is
A) $A \rightarrow B$
B) $B \rightarrow C$
C) $C \rightarrow D$
D) $A \rightarrow D$
Explanation
(a)
$A\overset{\ \ \ \ k_{1}\ \ \ \ }{\rightarrow}B\overset{\ \ \ \ k_{2}\ \ \ \ }{\rightarrow}C\overset{\ \ \ \ k_{3}\ \ \ \ }{\rightarrow}D$
$\because k_{3} > k_{2} > k_{1}$
As $k_{1}$ is slowest hence $A \rightarrow B$ is the rate determining step of the reaction
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.