(b) For zero order reaction $x = kt$ $= 0.2\ mol\ {dm}^{- 3}\ h^{- 1} \times \frac{30}{60}\ h$ $= 0.1\ mol\ {dm}^{- 3}$ Now, concentration $= 0.05\ mol\ {dm}^{- 3}$ Hence, initial concentration $= 0.1 + 0.05 = 0.15\ mol\ {dm}^{- 3}$
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