Q. The expression for rate constant of a first order chemical reaction is
A) $k = \frac{1}{t} \bullet \frac{x}{a(a - x)}$
B) $k = \frac{2.303}{t}\log_{10}\frac{a}{(a - x)}$
C) $k = \frac{x}{t}$
D) $k = \frac{1}{2t}\ \left\lbrack \frac{1}{(a - x)^{2}} - \frac{1}{a^{2}} \right\rbrack$
Explanation
The correct answer is Option B: $k = \frac{2.303}{t}\log_{10}\frac{a}{(a - x)}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.