Q. For the reaction, $2A + B \rightarrow$ products, the active mass of $B$ is kept constant, and that of $A$ is doubled. The rate of reaction will be then
A) Decrease 4 times
B) Decrease 2 times
C) Increase 4 times
D) Increase 2 times
Explanation
(c)
$2A + B \rightarrow$ products
Rate of reaction, $r_{1} = k\lbrack A\rbrack^{2}\lbrack B\rbrack$
If the concentration of $A$ become double then the rate will be
$r_{2} = k\lbrack 2A\rbrack^{2}\lbrack B\rbrack$
$r_{2} = 4k\lbrack A\rbrack^{2}\lbrack B\rbrack$
$r_{2} = 4r_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.