Q. A reaction was found to order with respect to the concentration of carbon monoxide. If the concentration of carbon monoxide is doubled, with everything else kept the same, the rate of reaction will
A) Remain unchanged
B) Triple
C) Increases by factor of four
D) Double
Explanation
(c)
$r \propto \lbrack CO\rbrack^{2}$
$r^{1} \propto \lbrack 2CO\rbrack^{2}$
$r^{1} \propto {4\lbrack CO\rbrack}^{2}$
Hence,
$\frac{r^{1} \propto 4\lbrack CO\rbrack^{2}}{r^{1} \propto \lbrack CO\rbrack^{2}}$
$r^{1} \propto 4r$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.