Q. The activation energy of exothermic reaction $A \rightarrow B$ 80 kJ $mol^{- 1}$. The heat of reaction is 200 kJ$mol^{- 1}\$. The activation energy for the reaction $B \rightarrow A$(in kJ $mol^{- 1}$) will be

A) 80
B) 120
C) 40
D) 280
Explanation

(d)
$E_{a}(A \rightarrow B) = 80\ kJ\ mol^{- 1}$
Heat of reaction $(A \rightarrow B) = 200\ kJ\ mol^{- 1}$
For $(B \rightarrow A)\ backward\ reaction,$
$E_{a}(B \rightarrow A) = E_{a}(A \rightarrow B) + heat\ of\ reaction$
$= 80 + 200 = 280$kJ $mol^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.