Q. For a hypothetical reaction $A + 2B \rightarrow 3C + D$ $d\lbrack C\rbrack/dt$ is equal to
A) $\frac{3d\lbrack A\rbrack}{dt}$
B) $- \frac{3}{2}\frac{d\lbrack B\rbrack}{dt}$
C) $- \frac{d\lbrack B\rbrack}{dt}$
D) $- \frac{d\lbrack A\rbrack}{dt}$
Explanation
(b)
$\frac{- d\lbrack A\rbrack}{dt} = - \frac{1}{2}\frac{d\lbrack B\rbrack}{dt} = \frac{1}{3}\frac{d\lbrack C\rbrack}{dt} = \frac{d\lbrack D\rbrack}{dt}$
$\frac{d\lbrack C\rbrack}{dt} = - \frac{3}{2}\frac{d\lbrack B\rbrack}{dt} = - \frac{3d\lbrack A\rbrack}{dt} = \frac{3d\lbrack D\rbrack}{dt}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.