Q. The rate constant for the reaction, $2N_{2}O_{5} \rightarrow 4{NO}_{2} + O_{2}$ is $3.0 \times 10^{- 5}\ s^{- 1}.$ If the rate is $2.40 \times 10^{- 5}$ then the concentration of $N_{2}O_{5}\ (in\ mol/L)$ is
A) 1.4
B) 1.2
C) 0.04
D) 0.8
Explanation
(d)
For a first order reaction,
rate$\ = k\lbrack reactant\rbrack$
$\lbrack reactant\rbrack = \frac{rate}{k}$
$\ = \frac{2.40 \times 10^{- 5}}{3.0 \times 10^{- 5}} = 0.8$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.