Q. Rate of a reaction can be expressed of by following rate expression Rate=k$\lbrack A\rbrack^{2}\lbrack B\rbrack,$ if concentration of A is reduced by half by what times concentration of B is to be increased to have same rate of reaction?

A) 4 times
B) 2 times
C) ¼ times
D) 8 times
Explanation

(a)
Given, $R_{1} = k\lbrack A\rbrack^{2}\lbrack B\rbrack$
Let concentration of B is changed by x times.
Then,
$R_{2} = k\lbrack A/2\rbrack^{2}\lbrack xB\rbrack$
$= k \times x/4\lbrack A\rbrack^{2}\lbrack B\rbrack$
$= x/4 \times k\lbrack A\rbrack^{2}\lbrack B\rbrack$
As $R_{2} = R_{1},thus\ x = 4$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.