Q. For the reaction$\ A + B \rightarrow C$, it is found that doubling the concentration of A increases the rate by four times and doubling the concentration of B doubles the reaction rate. What is the overall order of the reaction?
A) 4
B) 3/2
C) 3
D) 1
Explanation
(c)
$A + B \rightarrow C$
On doubling the concentration of A, rate of reaction increases by 4 times.
$\therefore\ \ \ \ \ \ \ rate\ \propto \lbrack A\rbrack^{2\ }$(w.r.t. A)
However, on doubling the concentration of B rate of reaction increases two times.
$\therefore\ \ \ \ \ \ \ rate\ \propto \lbrack B\rbrack^{2\ }(w.r.t.\ B)$
Thus, overall order of reaction =2+1=3
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.