Explanation

(b)
A graph between the log concentration (log c) of reactant and time t for the first order reaction gives a straight line, whose slope is equal to $- \frac{k}{2.303}$
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$\log_{10}C_{A} = - \frac{kt}{2.303} + \log_{10}\left( C_{A} \right)_{0}$
Hence, the order of the above reaction is one.