A drop of a solution $(volume\ = 0.05\ mL)$ contains $6 imes 10^{- 7}\$mol of$\ H^{+}.$ If the rate of disappearance of $\ H^{+}$ is $6.0 imes 10^{5}\ mol/L imes s,$ how long will it take for $H^{+}$ to disappear from the drop

Question

A drop of a solution $(volume\ = 0.05\ mL)$ contains $6 	imes 10^{- 7}\$mol of$\ H^{+}.$ If the rate of disappearance of $\ H^{+}$ is $6.0 	imes 10^{5}\ mol/L 	imes s,$ how long will it take for $H^{+}$ to disappear from the drop

Dr. Abubacker · Accepted Answer

(b)
$\left\lbrack H^{+} ightbrack = \frac{6 	imes 10^{- 7}\ mol}{5 	imes 10^{- 5}\ L} = 1.2 	imes 10^{- 2}M$
$rate = \frac{dx}{dt}\ or\ dt = \frac{dx}{rate} = \frac{1.2 	imes 10^{- 2}M}{6 	imes 10^{5}\ M/s}$
$= 2 	imes 10^{- 8}\ s$

Q. A drop of a solution $(volume\ = 0.05\ mL)$ contains $6 \times 10^{- 7}\$mol of$\ H^{+}.$ If the rate of disappearance of $\ H^{+}$ is $6.0 \times 10^{5}\ mol/L \times s,$ how long will it take for $H^{+}$ to disappear from the drop

Explanation

Reviewed by Dr. Abubacker

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