Q. The rate of the reaction $A \rightarrow$ product, at the initial concentration of $3.24 \times 10^{- 2}M$ is nine times its rate at another initial concentration of $1.2 \times 10^{- 3}M$. The order of the reaction is

A) $\frac{1}{2}$
B) $\frac{3}{4}$
C) $\frac{3}{2}$
D) $\frac{2}{3}$
Explanation

(d)
$9 = \left( \frac{3.24 \times 10^{- 2}}{1.2 \times 10^{- 3}} \right)^{n}$
$9 = \left( 3^{3} \right)^{2/3}$
order of the reaction is=2/3

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.