Q.
In the given graph the activation energy, $E_{a}$ for the reverse reaction will be
A) 150 kJ
B) 50 kJ
C) 200 kJ
D) 100 kJ
Explanation
(b)
In the given graph,
$E_{a} = E_{a}^{''} + \mathrm{\Delta}\ H$
where, $E_{a}^{''} =$activation energy of reverse reaction
$150 = E_{a}^{''} + 100$
$E_{a}^{''} = 50\ kJ$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.