Q. In the reaction $3A \rightarrow 2B$, rate of reaction $+ \frac{d(B)}{dt}$ is equal to
A) $- \frac{1}{3}\frac{d\lbrack A\rbrack}{dt}$
B) $- \frac{2}{3}\frac{d\lbrack A\rbrack}{dt}$
C) $+ \frac{2d\lbrack A\rbrack}{dt}$
D) $- \frac{3}{2}\frac{d\lbrack A\rbrack}{dt}$
Explanation
(b)
For the reaction,
$3A \rightarrow 2B$
$Rate = - \frac{1}{3}\frac{d\lbrack A\rbrack}{dt} = + \frac{1}{2}\frac{d\lbrack B\rbrack}{dt}$
$\therefore\ \ \ \ + \frac{d\lbrack B\rbrack}{dt} = - \frac{2}{3}\frac{d\lbrack A\rbrack}{dt}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.